It seems like there’s a slight discrepancy in the final roots given in the FAQ section compared to the actual calculated roots. Let’s clarify the correct roots based on the calculations:
Solving the Quadratic Equation 4X^2 – 5X – 12 = 0
Step-by-Step Solution:
Step 1: Identify the Constants
- a=4a = 4
- b=−5b = -5
- c=−12c = -12
Step 2: Calculate the Discriminant
- Discriminant Δ=b2−4ac\Delta = b^2 – 4ac
- b2=(−5)2=25b^2 = (-5)^2 = 25
- 4ac=4⋅4⋅(−12)=−1924ac = 4 \cdot 4 \cdot (-12) = -192
- Δ=25−(−192)=25+192=217\Delta = 25 – (-192) = 25 + 192 = 217
Step 3: Apply the Quadratic Formula
- Quadratic formula: X=−b±Δ2aX = \frac{-b \pm \sqrt{\Delta}}{2a}
- X=−(−5)±2172⋅4X = \frac{-(-5) \pm \sqrt{217}}{2 \cdot 4}
- X=5±2178X = \frac{5 \pm \sqrt{217}}{8}
Step 4: Find the Two Roots
- Approximating the roots using a calculator:
- X1=5+2178≈3.22X_1 = \frac{5 + \sqrt{217}}{8} \approx 3.22
- X2=5−2178≈−1.22X_2 = \frac{5 – \sqrt{217}}{8} \approx -1.22
Summary of the Solution:
Step | Action | Result |
---|---|---|
1 | Identify Constants | a=4,b=−5,c=−12a = 4, b = -5, c = -12 |
2 | Calculate Discriminant | Δ=217\Delta = 217 |
3 | Apply Quadratic Formula | X=5±2178X = \frac{5 \pm \sqrt{217}}{8} |
4 | Approximate Roots | X1≈3.22,X2≈−1.22X_1 \approx 3.22, X_2 \approx -1.22 |
Frequently Asked Questions:
- What Are The Roots Of 4x^2 – 5x – 12 = 0?
- The roots are X1≈3.22X_1 \approx 3.22 and X2≈−1.22X_2 \approx -1.22.
- How To Solve 4x^2 – 5x – 12 = 0?
- Use the quadratic formula: X=−b±b2−4ac2aX = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}.
- What Does 4x^2 – 5x – 12 = 0 Represent?
- It represents a quadratic equation with two real roots.
- Why Is 4x^2 – 5x – 12 = 0 Important?
- It’s important for understanding quadratic equations and their solutions.
Conclusion:
We have successfully solved the quadratic equation 4X2–5X–12=04X^2 – 5X – 12 = 0 using the quadratic formula. The roots, approximately 3.223.22 and −1.22-1.22, help us understand how to find solutions to quadratic equations and their practical applications. Keep practicing to enhance your skills in solving such equations!
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